# Solve 0.45 = (a - x(bcd + bce + bf)) / (a + x(bcg - bcd -bce -bf)) for x

#### vindiou

##### New member
Hi everyone,

0.45 = (a - x(bcd + bce + bf)) / (a + x(bcg - bcd -bce -bf))
x = ?

I'm stuck and I need help! (I'm a 56 yo guy and school classes are very far...)

Thanks!

Last edited by a moderator:

#### tkhunny

##### Moderator
Staff member
Hi everyone,

0.45 = (a - x(bcd + bce + bf)) / (a + x(bcg - bcd -bce -bf))
x = ?

I'm stuck and I need help! (I'm a 56 yo guy and school classes are very far...)

Thanks!
The appearance seems a bit pointless. Can you solve $$\displaystyle 0.45 = \dfrac{a - xH}{a+x(J-H)}$$, for x?

#### vindiou

##### New member
The appearance seems a bit pointless. Can you solve $$\displaystyle 0.45 = \dfrac{a - xH}{a+x(J-H)}$$, for x?
Thanks, I solved it, x = 0.55a / (0.45bcg + 0.55b(cd + ce + f)), merry xmas

#### JeffM

##### Elite Member
The appearance seems a bit pointless. Can you solve $$\displaystyle 0.45 = \dfrac{a - xH}{a+x(J-H)}$$, for x?
Ahh, I do not think it pointless at all. Finding the relatively simple in the seemingly complex is one of the skills that math teaches you.

#### Denis

##### Senior Member
Well, Sir Vindiou he no seem too interested...edited his post to a point!!

#### JeffM

##### Elite Member
Well, Sir Vindiou he no seem too interested...edited his post to a point!!
Which obviously entails that it cannot be pointless.

#### Denis

##### Senior Member
0.45 = (a - x(bcd + bce + bf)) / (a + x(bcg - bcd -bce -bf))
x = ?
Since you're solving for x, then the rest is assumed to be givens; so simplify:
u = bcd + bce + bf
v = (bcg - bcd -bce -bf

Equation becomes:
(a - xu) / (a + xv) = 9/20

Let us know if yer still alive Sir V !!