Solve 0.45 = (a - x(bcd + bce + bf)) / (a + x(bcg - bcd -bce -bf)) for x

vindiou

New member
Hi everyone,

0.45 = (a - x(bcd + bce + bf)) / (a + x(bcg - bcd -bce -bf))
x = ?

I'm stuck and I need help! (I'm a 56 yo guy and school classes are very far...)

Thanks!

Last edited by a moderator:

tkhunny

Moderator
Staff member
Hi everyone,

0.45 = (a - x(bcd + bce + bf)) / (a + x(bcg - bcd -bce -bf))
x = ?

I'm stuck and I need help! (I'm a 56 yo guy and school classes are very far...)

Thanks!
The appearance seems a bit pointless. Can you solve $$\displaystyle 0.45 = \dfrac{a - xH}{a+x(J-H)}$$, for x?

vindiou

New member
The appearance seems a bit pointless. Can you solve $$\displaystyle 0.45 = \dfrac{a - xH}{a+x(J-H)}$$, for x?
Thanks, I solved it, x = 0.55a / (0.45bcg + 0.55b(cd + ce + f)), merry xmas

JeffM

Elite Member
The appearance seems a bit pointless. Can you solve $$\displaystyle 0.45 = \dfrac{a - xH}{a+x(J-H)}$$, for x?
Ahh, I do not think it pointless at all. Finding the relatively simple in the seemingly complex is one of the skills that math teaches you.

Denis

Senior Member
Well, Sir Vindiou he no seem too interested...edited his post to a point!!

JeffM

Elite Member
Well, Sir Vindiou he no seem too interested...edited his post to a point!!
Which obviously entails that it cannot be pointless.

Denis

Senior Member
0.45 = (a - x(bcd + bce + bf)) / (a + x(bcg - bcd -bce -bf))
x = ?
Since you're solving for x, then the rest is assumed to be givens; so simplify:
u = bcd + bce + bf
v = (bcg - bcd -bce -bf

Equation becomes:
(a - xu) / (a + xv) = 9/20

Let us know if yer still alive Sir V !!