solve 2 + 8 *2*2/4-8/ (3-2/2) + 2^ 3, etc.

raymatt

New member
Joined
Sep 8, 2007
Messages
1
okay here is a couple problems can someone help me solve them

2 + 8 *2*2/4-8/ (3-2/2) + 2^ 3

(my answer is -2)

A=6.0,C=4.0


(A/(C+1)*8-6)/2+ (6Mod4\3)

(my answer is 1.8)

(C-A*3) + 5.4

(my answer is -8.6)
So where did I go wrong on these??????????
 
Re: please help

raymatt said:
okay here is a couple problems can someone help me solve them

2 + 8 *2*2/4-8/ (3-2/2) + 2^ 3

(my answer is -2)



So where did I go wrong on these??????????

Follow the order of operations. Start with what's inside the parentheses, and remember that you'll need to do the division BEFORE the subtraction:

2 + 8 * 2 * 2 / 4 - 8 / (3 - 1) + 2^3
2 + 8 * 2 * 2 / 4 - 8 / 2 + 2^3

Next, take care of the exponents:

2 + 8 * 2 * 2 / 4 - 8 / 2 + 8

Now, do any multiplications and divisions in order from left to right:

2 + 16 * 2 / 4 - 8 / 2 + 8
2 + 32 / 4 - 8 / 2 + 8
2 + 8 - 8 / 2 + 8
2 + 8 - 4 + 8

Finally, do additions and subtractions in order from left to right:

10 - 4 + 8
6 + 8
14

So....I get 14 as the value of this expression. I've showed every step individually. Hopefully you can follow the process.

For the other two problems, which involve A and C, were you given values to use for those variables? I can't help without knowing what those values are.
 
Top