D dayton1 New member Joined Oct 22, 2007 Messages 33 Oct 30, 2007 #1 This one was on a test, but something we had never seen the likes of before: (49 - 1/y^2)/(7 + 1/y)=1 (solve for y) so I assume that I would reduce first making it (7-1/y^2)/1+1/y)=1 I'm not sure what to do next......
This one was on a test, but something we had never seen the likes of before: (49 - 1/y^2)/(7 + 1/y)=1 (solve for y) so I assume that I would reduce first making it (7-1/y^2)/1+1/y)=1 I'm not sure what to do next......
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Oct 30, 2007 #2 no ... your first step of "reduction" is incorrect. start by multiplying every term in the numerator and denominator by y<sup>2</sup> ... (49y<sup>2</sup> - 1)/(7y<sup>2</sup> + y) now factor the numerator and denominator, then reduce.
no ... your first step of "reduction" is incorrect. start by multiplying every term in the numerator and denominator by y<sup>2</sup> ... (49y<sup>2</sup> - 1)/(7y<sup>2</sup> + y) now factor the numerator and denominator, then reduce.
