S Stine New member Joined Nov 29, 2006 Messages 49 Nov 30, 2006 #1 3y^2-19y=40 3y^2-19y-40=0 (3y-5) (1y+8) 3y-5=0+5 3y/3=5/3 y=5/3 or 1y+8=0-8 1y/1=-8/1 y=-8 Am I all good on this one? Thank you... :?

3y^2-19y=40 3y^2-19y-40=0 (3y-5) (1y+8) 3y-5=0+5 3y/3=5/3 y=5/3 or 1y+8=0-8 1y/1=-8/1 y=-8 Am I all good on this one? Thank you... :?

A arthur ohlsten Full Member Joined Feb 20, 2005 Messages 854 Nov 30, 2006 #2 let us check your answer [3y-5][y+8] clear bracket 3y^2+24y-5y-40 3y^2+19y-40 close but no cigar the original was 3y^2-19y-40 [3y+5][y-8] try this Arthur

let us check your answer [3y-5][y+8] clear bracket 3y^2+24y-5y-40 3y^2+19y-40 close but no cigar the original was 3y^2-19y-40 [3y+5][y-8] try this Arthur