Solve by factoring (roots and radicals) Did I complete this?

Stine

New member
Joined
Nov 29, 2006
Messages
49
3y^2-19y=40

3y^2-19y-40=0

(3y-5) (1y+8)

3y-5=0+5
3y/3=5/3
y=5/3

or

1y+8=0-8
1y/1=-8/1
y=-8

Am I all good on this one?
Thank you... :? :( :oops:
 

arthur ohlsten

Full Member
Joined
Feb 20, 2005
Messages
854
let us check your answer
[3y-5][y+8] clear bracket
3y^2+24y-5y-40
3y^2+19y-40 close but no cigar

the original was 3y^2-19y-40

[3y+5][y-8] try this
Arthur
 
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