dolphin_girl93
New member
- Joined
- Nov 2, 2009
- Messages
- 1
How would you solve these equations using common logarithms?
3^(x+4) = 2^(1-3x)
5^x + 125(5^-x)=30?
I thought for the first one I was supposed to equate bases but I don't know how you'd do that. So is that and I'm just not seeing it or something else?
For the second one again I thought you might equate bases but I think the 125(5^-x) is throwing me off?
3^(x+4) = 2^(1-3x)
5^x + 125(5^-x)=30?
I thought for the first one I was supposed to equate bases but I don't know how you'd do that. So is that and I'm just not seeing it or something else?
For the second one again I thought you might equate bases but I think the 125(5^-x) is throwing me off?