Solve For D

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mathdad

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Given H = (D^2 N)/2.5, solve for D.

Solution:

2.5H = [(D^2 N)/2.5][2.5]

2.5H = D^2 N

2.5H/N = D^2

sqrt{2.5H/N} = sqrt{D^2}

sqrt{2.5H/N} = D

What do you say?
 

Jomo

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No, your answer is incorrect.

You need to remember the following.

If A^2 =B (and B is not negative), then A = +/- sqrt(B)

So if D^2 = 2.5H/N . the D = +/- sqrt(2.5H/N)
 

mathdad

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No, your answer is incorrect.

You need to remember the following.

If A^2 =B (and B is not negative), then A = +/- sqrt(B)

So if D^2 = 2.5H/N . the D = +/- sqrt(2.5H/N)
I simply made a typo. The answer is not wrong. So, I forgot the plus and minus sign. I am not going to give myself a failing grade on my journey through college algebra.
 

Otis

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I simply made a typo. The answer is not wrong.
An answer that contains a typo is not correct because typos are mistakes.


So, I forgot the plus and minus sign.
What in the world is that comment suppose to mean? It sounds like whining. If you can't handle people checking your work (that is, pointing out mistakes), then why are you posting here?


I am not going to give myself a failing grade on my journey ...
I think you're jumping to wild conclusions, again.

:rolleyes:
 

Jomo

Elite Member
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I simply made a typo. The answer is not wrong. So, I forgot the plus and minus sign. I am not going to give myself a failing grade on my journey through college algebra.
No, the answer is not right. Right means 100% correct. If you make a mistake I will tell you so.
 

mathdad

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Moving on....
 
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