mathdad
Full Member
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- Apr 24, 2015
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Solve T = 2pi•sqr{L/32} for L.
Solution:
T = 2pi•sqr{L/32}
T/(2pi) = sqrt{L/32}
[T/(2pi)]^2 = [sqrt{L/32}]^2
(T^2)/4(pi)^2 = L/32
32(T^2)/4(pi)^2 = L
8(T^2)/(pi)^2 = L
Yes?
Note: Can someone check my work done on the question Solve Formula For h?
Solution:
T = 2pi•sqr{L/32}
T/(2pi) = sqrt{L/32}
[T/(2pi)]^2 = [sqrt{L/32}]^2
(T^2)/4(pi)^2 = L/32
32(T^2)/4(pi)^2 = L
8(T^2)/(pi)^2 = L
Yes?
Note: Can someone check my work done on the question Solve Formula For h?
