solve for N

[zarles]

hello, can any1 help me solve for N

F = A(1+i)^N + (P/i)[(1+i)^N ? 1]


after solving i get


N = ( log(F + (P/i)) - log(A) - log(P/i) / ( 2 * log(1+i) ))


do you guys agree?

thanks!

 

[tkhunny]

I prefer this, \(\displaystyle N = \frac{ln\left(\frac{P+Fi}{P+Ai}\right)}{ln(1+i)}\).

Are tehy the same? I can't really tell where your intent is in ever case of parentheses.

It may be beneficial to break it up a bit. Solve first for (1+i)^N.

This gives \(\displaystyle (1+i)^{N} = \frac{P+Fi}{P+Ai}\)

You can get a little better handle on which diretion things are going.