C cpohlman New member Joined Feb 1, 2006 Messages 1 Feb 1, 2006 #1 This is the problem: f(x)=(x-.2)/(x+.5) Find the inverse. I know I have to solve for x, but I can't remember how to do that.
This is the problem: f(x)=(x-.2)/(x+.5) Find the inverse. I know I have to solve for x, but I can't remember how to do that.
C ChaoticLlama Junior Member Joined Dec 11, 2004 Messages 199 Feb 1, 2006 #2 replace x with f(x) and f(x) with x, then solve for x. That should make things a little easier.
U Unco Senior Member Joined Jul 21, 2005 Messages 1,134 Feb 1, 2006 #3 cpohlman said: This is the problem: f(x)=(x-.2)/(x+.5) Find the inverse. I know I have to solve for x, but I can't remember how to do that. Click to expand... \(\displaystyle \mbox{ y = \frac{x - \frac{1}{5}}{x + \frac{1}{2}}}\) Multiply both sides by \(\displaystyle \mbox{x + \frac{1}{2}}\) (note restriction in domain) \(\displaystyle \mbox{ y\left(x + \frac{1}{2}\right) = x - \frac{1}{5}}\) Distribute the left-hand side, group x terms to one side, and factor out x to solve for x.
cpohlman said: This is the problem: f(x)=(x-.2)/(x+.5) Find the inverse. I know I have to solve for x, but I can't remember how to do that. Click to expand... \(\displaystyle \mbox{ y = \frac{x - \frac{1}{5}}{x + \frac{1}{2}}}\) Multiply both sides by \(\displaystyle \mbox{x + \frac{1}{2}}\) (note restriction in domain) \(\displaystyle \mbox{ y\left(x + \frac{1}{2}\right) = x - \frac{1}{5}}\) Distribute the left-hand side, group x terms to one side, and factor out x to solve for x.
