Solve for x

Is the equation actually:

[MATH]\log_{10}(x)=3[/MATH] ?
 
Okay, so then we have:

[MATH]\log\left(10^x\right)=3[/MATH]
Are we to assume the base of the logarithm is 10?
 
Okay, so it's:

[MATH]\log_{10}(x)=3[/MATH]
Surely, you have been told that:

[MATH]\log_a(b)=c[/MATH]
Implies:

[MATH]b=a^c[/MATH]
Right?
 
Have you been provided with any material to review, that states (at least the main) properties of logrithms?

But, using what I posted, can you now solve the equation?
 
Have you been provided with any material to review, that states (at least the main) properties of logrithms?
But, using what I posted, can you now solve the equation?
Actually elsewhere this person has said that s/he has never had any kind of algebra but is enrolled in the University of Phoenix.
Has been misplaced totally.
 
Have you at least been told the definition of "logarithm"? I would hope that you realize you cannot solve a problem involving a concept (like "logarithm") without knowing its definition!

\(\displaystyle y= log_a(x)\) if and only if \(\displaystyle x= a^y\). Here you are given that \(\displaystyle log_{10}(x)= 3\) so that \(\displaystyle x= 10^3= 1000\).
 
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