log4 1/64 = x 4^x = 1/64 4^x = 1/3^4 4^x = 3^-4 x = -4
N NEHA Junior Member Joined Oct 27, 2006 Messages 90 Dec 4, 2006 #1 log4 1/64 = x 4^x = 1/64 4^x = 1/3^4 4^x = 3^-4 x = -4
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Dec 4, 2006 #2 Re: solve for x Hello, NEHA! A simple error . . . log4(164) = x\displaystyle \log_4\left(\frac{1}{64}\right) \:=\: xlog4(641)=x 4x = 164\displaystyle 4^x \:= \:\frac{1}{64}4x=641 4x =134 ⇐ \displaystyle 4^x \:= \frac{1}{3^4}\;\Leftarrow\;4x=341⇐ Here! .Of course, you meant: 143\displaystyle \,\frac{1}{4^3}431 Click to expand... Then we have: 4x = 4−3 ⇒ x = −3\displaystyle 4^x\:=\:4^{-3}\;\;\Rightarrow\;\;x\,=\,-34x=4−3⇒x=−3
Re: solve for x Hello, NEHA! A simple error . . . log4(164) = x\displaystyle \log_4\left(\frac{1}{64}\right) \:=\: xlog4(641)=x 4x = 164\displaystyle 4^x \:= \:\frac{1}{64}4x=641 4x =134 ⇐ \displaystyle 4^x \:= \frac{1}{3^4}\;\Leftarrow\;4x=341⇐ Here! .Of course, you meant: 143\displaystyle \,\frac{1}{4^3}431 Click to expand... Then we have: 4x = 4−3 ⇒ x = −3\displaystyle 4^x\:=\:4^{-3}\;\;\Rightarrow\;\;x\,=\,-34x=4−3⇒x=−3
