S sfin New member Joined Mar 9, 2007 Messages 8 Mar 23, 2007 #1 Solve the equation: 1/2 log(x+2) + log5 = 1 log(x+2)^1/2 + log5 = 1 log5(x+2)^1/2 = 1 When I get to here, the 5(x+2)^1/2 is throwing me off. Am I even going about this right?
Solve the equation: 1/2 log(x+2) + log5 = 1 log(x+2)^1/2 + log5 = 1 log5(x+2)^1/2 = 1 When I get to here, the 5(x+2)^1/2 is throwing me off. Am I even going about this right?
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Mar 23, 2007 #2 Your start looks fine. Now convert the log equation to its equivalent exponential form: . . . . .If log<sub>b</sub>(x) = y, . . . . .then b<sup>y</sup> = x. Then solve the resulting radical equation. Eliz.
Your start looks fine. Now convert the log equation to its equivalent exponential form: . . . . .If log<sub>b</sub>(x) = y, . . . . .then b<sup>y</sup> = x. Then solve the resulting radical equation. Eliz.
