Hi.
Any one have an idea how to solve this question?
Solve the differential equation? dy/dx= (x^2+y)^2 - 2x?
dy/dx= (x^2+y)^2 - 2x? Hint let u =x^2+y
Thanks.
You were given a hint - what did you do with it?
y = u - x^2
dy/dx = du/dx - 2x
then
du/dx - 2x = (x^2 + y)^2 - 2x
continue.....
What did you get after substitution.Hi.
I thought i needed to solve it like this :
u =y+ x^2
Then
du/dx=2x dy/dx--------(dy/dx)=(1/2x)(du/dx)
Then I substitute (dy/dx)=(1/2x)(du/dx) into original equation. ... OKay - do it!
Thanks.
Hi.
I thought i needed to solve it like this :
u =y+ x^2
Then
du/dx=2x + dy/dx--------(dy/dx)=(du/dx) - 2x ........ corrected
Then I substitute (dy/dx) = (du/dx) - 2x into original equation. ........ corrected
Thanks.