Solve the system of linear equations by either substitution or elimination;

[gijas]

(1) {-2/5x+3y=-4
(2) {0=6x-y-5

Now I would assume that in the second equation 0=6x-y-5 you would try to get the 6x and the -y to one side like this.

-6x+y=-5?

After this I tried using the elimination method by multiplying either -2/5x=3y=-4 by -5 to get rid of the fraction which would come out as 2x+-15y=20 or multiplying the second equation -6x+y=-5 by -3 to get 18x-3Y=15? Either way I get fractions for answers (large fractions) and not whole numbers.

I even tried the substitution method and get the same. Whats the trick here?


PS Need help ASAP.

 

[gijas]

Of course you would say that. Anyway, I get for this answer; (x=8/5, y=23/5) using the elimination method and multiplying equation (1) by -5 and equation (2) by 15?

Here's someone elses answer not sure if its correct;

-2/5x+3y=-4 ....(1) and 0=6x-y-5 => 6x-y = 5 ...(2) Multiply equation 2 by 3 => 18x-3y =15 ....(3)
Add equation number number 1 and 3 =>18x-2x/5 = 15-4 = 11
=> x = 5/8 ,Plug x value in equation 1 => y = -5/4