If the instructions really told you to solve for "K", then you should point out to your instructor that there is no "K" in the equation, only a "k" (which is, of course, an entirely different variable). :shock:chelser13 said:x^2 + 2kx + 3(k+1) =0
Solve for K. K is a real positive number.
You have one equation with two variables. It is impossible to solve for a unique numerical solution. Were you perhaps supposed to solve for x "in terms of k", and then, starting over again at the beginning, solve for k "in terms of x"?chelser13 said:sorry i should have said that first you are to solve for x then solve for k
No: "each side" means each side of the equal sign.chelser13 said:so far i have gotten x to one side and k on the other:
(x^2+3)+(2kx+3k)=0