Solving 2nd order nonlinear diff eq

borkborkmath

New member
Joined
Mar 4, 2011
Messages
16
I have the original equation as y'' +1.4y^2y' - 1.4y'+2y = 0; y(0) = 0, y'(0) = -1
I read that to solve this I need to break this into two 1st order differential equations, which i do through subsitution, getting:
x_1' = x_2; x_1(0) = 0 and
x_2' = -1.4x_1x_2 - 1.4x_2 + 2x_1; x_2(0) = -1

but how does this help me? I still cant seem to solve the DEs
I'm pretty sure i need to solve x_2' to get x_1 then i can get the exact solution to y. but i'm at a loss of what to do now.
 

CurveGuy

New member
Joined
Jul 22, 2020
Messages
9
I have the original equation as y'' +1.4y^2y' - 1.4y'+2y = 0; y(0) = 0, y'(0) = -1
Would a numerical solution do the job for you? If so try my app FC-Compiler, its freeware, and if that does it for you.
y2dot = -(1.4 * y**2 * ydot - 1.4 * ydot+2 * y) with initial values, integrate, and you should have an answer.
 
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