Solving a Polynomial

rotard

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Jul 5, 2010
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P(t)=-.00006t^3+.016t^2+7t+1200
Solve for t = 0

I can get as far as solving by grouping the -.00006t^3 with 7t and .016t^2 with 1200.
-.00006t(t^2-116667).016(t^2+75000)=0
I don't really see where to go from here.

I feel the the two extremes of factoring very large and very small numbers is throwing me off.
Any help would be appreciated.
Thanks,
Matt
 
rotard said:
P(t)=-.00006t^3+.016t^2+7t+1200
Solve for t = 0

I can get as far as solving by grouping the -.00006t^3 with 7t and .016t^2 with 1200.
-.00006t(t^2-116667).016(t^2+75000)=0
I don't really see where to go from here.

I feel the the two extremes of factoring very large and very small numbers is throwing me off.
Any help would be appreciated.
Thanks,
Matt

Have you taken a course in Calculus?

Using calculus - I get the first root as 546.8740637 - not a simple one.
 
rotard said:
P(t)=-.00006t^3+.016t^2+7t+1200
Solve for t = 0

I can get as far as solving by grouping the -.00006t^3 with 7t and .016t^2 with 1200.
-.00006t(t^2-116667).016(t^2+75000)=0
I don't really see where to go from here.

I feel the the two extremes of factoring very large and very small numbers is throwing me off.
Any help would be appreciated.
Thanks,
Matt

If you are REALLY asked to "solve for t = 0," then what you need to do is substitute 0 for t:

if P(t) = -0.00006t^3 + 0.016t^2 + 7t + 1200, then
P(0) = -0.00006*(0)^3 + 0.016*(0)^2 + 7*(0) + 1200

and it is just arithmetic.

Perhaps I've missed something, but AS STATED, that is how the problem should be "solved."
 
Mrs? is absolutely correct ....

I misread the problem - and thought that the question was to find the "zero" (or root) of the polynomial.
 
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