J joelblair New member Joined Jan 16, 2008 Messages 2 Jan 16, 2008 #1 2x+3=3/2 Solve for x x okay here is the deal I solver for x and get x=6 but the book says it is -6 or S={-6} where was my mistake? or is the book wrong?
2x+3=3/2 Solve for x x okay here is the deal I solver for x and get x=6 but the book says it is -6 or S={-6} where was my mistake? or is the book wrong?
L Loren Senior Member Joined Aug 28, 2007 Messages 1,299 Jan 16, 2008 #2 I got -6. But, how can we point out your error when you don't show us your work?
J joelblair New member Joined Jan 16, 2008 Messages 2 Jan 16, 2008 #3 2(x+3)=3x right? 2x+6=3x right? -2x from both sides x=6 no?
M Mrspi Senior Member Joined Dec 17, 2005 Messages 2,127 Jan 16, 2008 #4 joelblair said: 2(x+3)=3x right? 2x+6=3x right? -2x from both sides x=6 no? Click to expand... Um, no. The numerator of the first fraction was (2x + 3). So, when you cross-multiply here's what you have: 2(2x + 3) = 3(x) Now continue.....
joelblair said: 2(x+3)=3x right? 2x+6=3x right? -2x from both sides x=6 no? Click to expand... Um, no. The numerator of the first fraction was (2x + 3). So, when you cross-multiply here's what you have: 2(2x + 3) = 3(x) Now continue.....