BaseballB6236
New member
- Joined
- Sep 20, 2010
- Messages
- 9
I'm having difficulty solving this equation:
13^(-x-9) = 16 ^ (-8x)
Write your answer as an expression involving base-10 logarithms.
What I have so far:
log base13 13^ (-x-9) = log base13 16 ^(-8x)
-x-9 = log base13 16^(-8x)
-x-9 = -8x (log 16/log 13)
(-x-9)/(-8x) = (log 16/log 13)
13^(-x-9) = 16 ^ (-8x)
Write your answer as an expression involving base-10 logarithms.
What I have so far:
log base13 13^ (-x-9) = log base13 16 ^(-8x)
-x-9 = log base13 16^(-8x)
-x-9 = -8x (log 16/log 13)
(-x-9)/(-8x) = (log 16/log 13)