# Solving Equatiosn withParentheses

#### Takitia

##### New member
Not sure on what to do next.

7(3x+4)=8(2x+5)+13
21x+28 =16x40+13 after this point I am confused and stuck. I know I am
to combine like terms, but not sure which one to do first.

#### jonboy

##### Full Member
Hello, Takita!

Great awareness so far of the Distributive Property so far!

$$\displaystyle \L \;21x\,+\,28\,=\,16x\,+\,40\,+\,13$$

First since you have normal, like natural numbers on the right side of the equation, combine them:

$$\displaystyle \L \;21x\,+\,28\,=\,16x\,+\,53$$

Now you can either subtract the 21x or the 16x from both sides of the equation; But the subtraction of 16x causes no negatives for the coefficient x so let's do that:

$$\displaystyle \L \;5x\,+\,28\,=\,53$$

...Now just subtract 28 from both sides:$$\displaystyle \L \;5x\,=\,25\;\;\Rightarrow\;\;x\,=\,5$$