Solving for k + n where n < 100

[mameha]

Hi there!

I'm having some difficulty with this problem which was taken from a practice question on the GRE:

If 72.42 = k(24 + n/100), where n < 100 and k and n are positive integers, then k + n is equal to...

You're given 5 answer choices (15, 16, 17, 18, and 19).

I tried simplifying the equation to:

k(2400 + n) = 7242

But I'm still not sure what the best approach to this would be (where I could go through the problem reasonably quickly).

Any help would be very much appreciated!

 

[wjm11]

If 72.42 = k(24 + n/100), where n < 100 and k and n are positive integers, then k + n is equal to...

You're given 5 answer choices (15, 16, 17, 18, and 19).

n < 100 => n/100 < 1
k is an integer, so k times another integer (24) is going to be an integer, too.
Thus, 24k must be the “72” and kn/100 must be the “.42.”

Does that help?

 

[mameha]

If 72.42 = k(24 + n/100), where n < 100 and k and n are positive integers, then k + n is equal to...

You're given 5 answer choices (15, 16, 17, 18, and 19).

n < 100 => n/100 < 1
k is an integer, so k times another integer (24) is going to be an integer, too.
Thus, 24k must be the “72” and kn/100 must be the “.42.”

Does that help?

Yes! That makes sense now, thanks very much for helping me.