solving for lambda: 5/(1 - lambda)^2 = 9/(1 + lambda)^2

[Guest]

Can't figure out how to solve for λ, here's the problem:

5 / ((1-λ)^2) = 9 / ((1+λ)^2)

any suggestions?

 

[pka]

You can't solve \(\displaystyle 5 + 10\lambda + 5\lambda ^2 = 9 - 18\lambda + 9\lambda ^2 ??\)

 

[Guest]

wow. yes, i can solve that as a matter of fact, i was just being stupid while posting that apparently. thanks for pointing that out though.

 

[Denis]

solving for lambda: 5/(1 - lambda)^2 = 9/(1 + lambda)^2

why keep it worded "difficult looking" like that?

solving for x: 5 / (1 - x)^2 = 9 / (1 + x)^2 : get my drift?