Solving for real numbers of X

[thomforde21]

Solve for all real numbers of x which make the equation true.
(HINT: there are 5 values of x that make the equation true. Recall the laws of exponents; recall the importance of the discriminant.)

(x^2 + 7x + 11) ^(x^2 + 16x + 15) = 1

The second equation is raised as an exponent


I cant figure this problem out at all
if someone could help me out that would be super!

thanks!

 

[Denis]

Hint: anything to the power 0 = 1

 

[thomforde21]

Sorry i don't know what you mean by that

 

[thomforde21]

okay never mind i knew that hint but i still can't figure it out!

 

[stapel]

If the left-hand side is equal to the right-hand side, then what must be the value of the power?

If the power is equal to that value, what equation do you get?

How do you solve that sort of equation?

:wink:

 

[Deleted member 4993]

Hint: anything to the power 0 = 1

Except

\(\displaystyle 0^0 \, = \, nde\)

 

[Denis]

http://www.google.ca/search?hl=en&q=0%5 ... =&aq=f&oq=

 

[Deleted member 4993]

Okay .. Sir Dennis ... I stand corrected....

 

[Denis]

Finally made your 1st mistake this year ? :mrgreen:

 

[Deleted member 4993]

Finally made your 1st mistake this year ? :mrgreen:

No that was ignorance - failure to keep up with time (refusal to change with time.....) .

 

[Denis]

Well, not all that bad....a horse and buggy needs no fuel...
plus makes you the "hit of the freeway" :wink:

 

[mmm4444bot]

… a horse and buggy needs no fuel …

Huh? :?

The only horse that needs no fuel is a dead horse.