solving for variable in exponent: 10^2x = 9

[jesusphreek82]

ok im not thinking straight.... i dont know how to solve for a variable (thats an exponent)

ex: 10^2x =9

i know it seems easy but im too smart =)

 

[pka]

\(\displaystyle \L
\begin{array}{rcl}
10^{2x} &=& 9 \\
\left( {2x} \right)\ln (10) &=& \ln (9) \\
x &=& \frac{{\ln (9)}}{{2\ln (10)}} \\
\end{array}\)