Solving for W

Brucer

New member
Joined
Nov 12, 2010
Messages
2
I guess I am confused.

I did a hundred of these problems correctly and then got the incorrect answer for this one. The problem is simply P=2L+2W solve for W.

When I divided both side by 2 I got rid of both the 2's in 2l and 2W so that I ended up with (P/2)-L=W; whereas the actual answer is (P-2L)/2=W.

Apparently when you divide the side of 2L+2W by two you only get rid of the 2 in front of the W and not the two in front of the L. Is this correct?

Can someone explain this to me?

Brucer
 

galactus

Super Moderator
Staff member
Joined
Sep 28, 2005
Messages
7,216
The answers are equivalent. Your solution and the other one are the same thing.

\(\displaystyle \frac{P-2L}{2}=\frac{P}{2}-\frac{2L}{2}=\frac{P}{2}-L\)
 

Brucer

New member
Joined
Nov 12, 2010
Messages
2
I must have done to many problem and my brain turned to mush.

Thanks for the nice reply.

Brucer
 
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