solving for x

[giuly]

im not sure on how to start solving for x on this problem 20=16+80e^-0.254x if someone could help i would appreciate it

 

[wjm11]

im not sure on how to start solving for x on this problem 20=16+80e^-0.254x if someone could help i would appreciate it

20=16+80e^-0.254x

First subtract 16 from both sides, then divide both sides by 80:

(20 – 16)/80 = e^(-.254x)

Next, to get x out of the exponent, take the natural log of both sides and simplify:

ln [(20 – 16)/80] = ln [e^(-.254x)]
ln (4/80) = (-.254x)(ln(e))
ln (1/20) = (-.254x)

Finally, divide both sides by (-.254) to get x by itself:

X = [ln (1/20)]/(-.254)

 

[giuly]

thank you very much