J jwpaine Full Member Joined Mar 10, 2007 Messages 719 Apr 7, 2007 #1 Lets say for y = log3^x find log3^x = 9 I know, intuitively, that 3*3 = 9, so x = 2 but how do I solve for x, with something like this: log3^x = 5 We just started logarithmic functions....and I'm confused. Thanks.
Lets say for y = log3^x find log3^x = 9 I know, intuitively, that 3*3 = 9, so x = 2 but how do I solve for x, with something like this: log3^x = 5 We just started logarithmic functions....and I'm confused. Thanks.
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Apr 7, 2007 #2 \(\displaystyle \L\begin{array}{l} \log (3^x ) = x\log (3) = 5 \\ x = \frac{5}{{\log (3)}} \\ \end{array}\)
\(\displaystyle \L\begin{array}{l} \log (3^x ) = x\log (3) = 5 \\ x = \frac{5}{{\log (3)}} \\ \end{array}\)
