solving radical equation: sqrt[7 - x] - 5 = sqrt[6 - x]

[Jaskaran]

I have a problem, √(7-x) - 5 = √(6-x)

I'm confused on how to approach it, should I add the five to the other side...

But that would give me (after squaring the equation)

7 - x = 6 - x +10√(6-x) +25

Where to from there?!

 

[stapel]

Isolate the radical, and square everything again.

Eliz.

 

[Jaskaran]

So it's:


7 - x = 6 - x +10√(6-x) +25

-10√(6-x) = 24

100(6-x) = 240

6 - x = 24

x = -18

?

 

[stapel]

-10√(6-x) = 24

100(6-x) = 240

How did you get that 24² equalled 240...?

Eliz.

 

[Jaskaran]

Whoops. :lol: