Solving trig equations

For the first one, we get:

[MATH]\sin(5x)=\pm1[/MATH]
This implies:

[MATH]5x=\frac{\pi}{2}+k\pi=\frac{\pi}{2}(2k+1)[/MATH] where \(k\in\mathbb{Z}\)

Hence:

[MATH]x=\frac{\pi}{10}(2k+1)[/MATH]
Does this make sense? What do you get when factoring the second equation?
 
I gave a complete solution for the first one, and I am hoping you will show you work on the second.
 
The [first] one is different[.] I figured the second one[.]
I tried to parse your wording, above. (Your last post is not clear, regarding what you're working on now or what kind of help you need.)

Please follow the forum guidelines (see the Read Before Posting notice). Show what you've started on the exercise you need help with, or explain why you're stuck.

In the future, please start a new thread for each new exercise. Cheers!

\(\;\)
 
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