Unless your are required to use a particular formula, I would take the arccot of 1 and add 20.
\(\displaystyle cot(x-20)=1\)
\(\displaystyle x-20=cot^{-1}(1)\)
\(\displaystyle x=cot^{-1}(1)+20\)
Tangent and cotangent have a period of 180 degrees. Once you have your first
answer, add 180.
For that matter, you could solve \(\displaystyle tan(x-20)=1\)and get the same thing.