M mike10210 New member Joined Mar 1, 2009 Messages 2 Mar 1, 2009 #1 My math teacher gave this problem on my homework, and i have no idea how to do it. :?: sin(6x)=cos(9x) do you have to use the double angle formula? but that is sin(2a)=2sin(a)cos(a) so it still has two variables. Can someone please help me.
My math teacher gave this problem on my homework, and i have no idea how to do it. :?: sin(6x)=cos(9x) do you have to use the double angle formula? but that is sin(2a)=2sin(a)cos(a) so it still has two variables. Can someone please help me.
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Mar 1, 2009 #2 Re: Hard Trig Problem sin(6x)=cos(9x) You could try the addition formulas for sine and cosine. Using degrees, try some values starting with x=6. There are 4 more up to x=90. Starting with x=6, try increments of 24 up to x=90.
Re: Hard Trig Problem sin(6x)=cos(9x) You could try the addition formulas for sine and cosine. Using degrees, try some values starting with x=6. There are 4 more up to x=90. Starting with x=6, try increments of 24 up to x=90.
M mike10210 New member Joined Mar 1, 2009 Messages 2 Mar 1, 2009 #3 Re: Hard Trig Problem sin(6x)=cos(9x) Thank you for your help.
