Hey! im currently stuck on a combinatorial question and would appreciate if someone could help ´ , basically its a special game of poker 3 cards are on the table and each player gets to take 2 cards , the 3 cards on the table can be counted in for everyone. So basically there are 3 people playing Ida, Andy and James we know that Ida has spades queen and spades 10 and on the table there is spades ace, diamonds queen and clubs ten so the question is:"how many different kind of combinations of cards can Andy and James have so BOTH of them has a better pokerhand than Ida" i have gotten that Andy or james can seperatly have 33 combinations of different cards to have a better pokerhand than ida (if it was to be a 1v1) but im not quite sure how to do it when both has to have better, doesnt it depend on which cards that Andy/James picks up?
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