Specific Problem help please

I

Ice

New member
Joined
Feb 1, 2006
Messages
2
If x,y, and z are integers greter than 1 where xy= 12 and yz=45, which of the following must be true ?
A.) x <y<z
B.) x<z<y
C.) y<x<z
D.)Z<x<y
E) Z<y<X


Can someone please point out what I'm missing evidently!
 
Ice said:
If x,y, and z are integers greter than 1 where xy= 12 and yz=45, which of the following must be true ?
A.) x <y<z
B.) x<z<y
C.) y<x<z
D.)Z<x<y
E) Z<y<X


Can someone please point out what I'm missing evidently!
Click to expand...

x, y and z are all integers greater than 1.

Since xy = 12, there are only a few possibilities for x and y:
x = 2 and y = 6
x = 6 and y = 2
x = 3 and y = 4
x = 4 and y = 3

We also know that yz = 45
If y is 6, 2, or 4, we won't get an integer for z. If y = 3, then z = 15.

And if y = 3, we also know that x = 4.

We have the only possible values for x, y and z....you should be able to determine the correct answer choice.

Maybe I'm the one who is missing something obvious....but this seems to me to be the way to attack the problem.
 
Mrspi said:
Ice said:
If x,y, and z are integers greter than 1 where xy= 12 and yz=45, which of the following must be true ?
A.) x <y<z
B.) x<z<y
C.) y<x<z
D.)Z<x<y
E) Z<y<X


Can someone please point out what I'm missing evidently!
Click to expand...

x, y and z are all integers greater than 1.

Since xy = 12, there are only a few possibilities for x and y:
x = 2 and y = 6
x = 6 and y = 2
x = 3 and y = 4
x = 4 and y = 3

We also know that yz = 45
If y is 6, 2, or 4, we won't get an integer for z. If y = 3, then z = 15.

And if y = 3, we also know that x = 4.

We have the only possible values for x, y and z....you should be able to determine the correct answer choice.

Maybe I'm the one who is missing something obvious....but this seems to me to be the way to attack the problem.
Click to expand...

so what you;'re saying is y(3)< x (4) < z (15)?

but what if xy=12 u do X(2) Y (6)
and yz=45 y(6) Z must equal 9
So X (2) < Y (6) < Z (9)

I cant figure out whether it's A or C !
 
Because xy=12 then y=1,2,3,4,6, or 12.
Because yz=45 then y=1,3,5,9,15, or 45.
Looking at the possibilities for y, what must y equal?
 
O MY goodness you reply to this guy? but not me? hmm...that's not right. :evil:

Please respond to my question.
 
hollerback1 said:
O MY goodness you reply to this guy? but not me? hmm...that's not right. :evil:

Please respond to my question.
Click to expand...

Calm down, would you? There is no paid staff here to help you. Expect to wait hours, if not days for a response.
 
hollerback1 said:
O MY goodness you reply to this guy? but not me? hmm...that's not right.
Click to expand...
Since when does anybody here "owe" you preferential treatment? You've received replies and have shown absolutely no effort. Why does that mean that you "deserve" more, and that none of the volunteers here is "allowed" to help anybody else until you grant them permission?!?

...and you really wonder why some hesitate to deal with you...?

Eliz.
 
hollerback1 said:
O MY goodness you reply to this guy? but not me? hmm...that's not right. :evil:
Click to expand...
Actually his is just a much more interesting problem!
At is all there is to it!
 
Could you please help me with this problem?

3x + 6 = 12
___ __ ____
x+2 x x²+2x

I know that my demoninators are x+2, x, and I think x(x+2).
This is what I thought I should do.

3x(x)x(x+2) + 6(x+2)x(x+2) = 12(x)(x+2)
3x²(x²+2) + 6x+12(x²+2) = 12x(x+2)
Please help me.
Thanks
 
ymurray said:
Could you please help me with this problem?

3x + 6 = 12
___ __ ____
x+2 x x²+2x

I know that my demoninators are x+2, x, and I think x(x+2).
This is what I thought I should do.

3x(x)x(x+2) + 6(x+2)x(x+2) = 12(x)(x+2)
3x²(x²+2) + 6x+12(x²+2) = 12x(x+2)
Please help me.
Thanks
Click to expand...

Why did you hijack this person's thread? There's so much free space here. START YOUR OWN.
 
problem

Okay, I think the only solution is x=4, y=3, and z=15.
Therefore, i think answer is C!
 
ymurray said:
Could you please help me with this problem?

3x + 6 = 12
___ __ ____
x+2 x x²+2x

I know that my demoninators are x+2, x, and I think x(x+2).
This is what I thought I should do.

3x(x)x(x+2) + 6(x+2)x(x+2) = 12(x)(x+2)
3x²(x²+2) + 6x+12(x²+2) = 12x(x+2)
Please help me.
Thanks
Click to expand...
Notice that x(x+2) is the lowest common denominator. If we multiply both sides by x(x+2), we have: 3x(x) + 6(x+2) = 12.

But also note that when we multiply out a denominator -- that is, multiplying both sides by x(x+2) -- we must ensure that no denominator was zero. So x cannot equal zero -- otherwise 6/x has a zero denominator -- and cannot equal -2 -- otherwise 3x/(x+2) has a zero denominator, not to mention the 12/(x(x+2)) term.

~~~~~~~~~~~
Next time begin a new thread with a new question. That said, capatalisation=shouting. Ignore those people.
 
You must log in or register to reply here.
Top