[SPLIT] rational expression b+2/(2b^-b-1) - 1/(b-1)

[tiggersrule]

Hi, I have a rational expressions question I don't understand. The question is b+2/(2b^-b-1) - 1/(b-1). I understand how to factor the bottom (2b+1)(b-1) but am confused as to (b+2) - 1, which would be? Also, with (2b+1)(b-1) - (b-1) would that make it -b-1 on bottom. this is very confusing to me. Thanks for any help.

 

[stapel]

What were the instructions? What are you supposed to be doing with this?

When you reply, please include a clear listing of what you have tried so far. Thank you!

Eliz.

 

[skeeter]

\(\displaystyle \frac{b+2}{2b^2-b-1} - \frac{1}{b-1}\)

\(\displaystyle \frac{b+2}{(2b+1)(b-1)} - \frac{1}{b-1}\)

\(\displaystyle \frac{b+2}{(2b+1)(b-1)} - \frac{(2b+1)1}{(2b+1)(b-1)}\)

\(\displaystyle \frac{b+2 - (2b+1)}{(2b+1)(b-1)}\)

\(\displaystyle \frac{b+2 - 2b-1}{(2b+1)(b-1)}\)

\(\displaystyle \frac{1-b}{(2b+1)(b-1)}\)

\(\displaystyle -\frac{1}{2b+1}\)