N nigel New member Joined Sep 9, 2006 Messages 8 Oct 5, 2006 #1 Put y^2 - 4x - 6y + 9 = 0 into standard form. Is the answer as follows? x = (1/4)(y - 3)^2 please just tell me if the answer is correct, or if not what is the correct answer Thank You
Put y^2 - 4x - 6y + 9 = 0 into standard form. Is the answer as follows? x = (1/4)(y - 3)^2 please just tell me if the answer is correct, or if not what is the correct answer Thank You
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 Oct 5, 2006 #2 How does your book define "standard form"? (There is no fixed meaning to this term, is why I ask.) Thank you. Eliz.
How does your book define "standard form"? (There is no fixed meaning to this term, is why I ask.) Thank you. Eliz.
M Mrspi Senior Member Joined Dec 17, 2005 Messages 2,116 Oct 5, 2006 #3 nigel said: Put y^2 - 4x - 6y + 9 = 0 into standard form. Is the answer as follows? x = (1/4)(y - 3)^2 please just tell me if the answer is correct, or if not what is the correct answer Thank You Click to expand... IF your book defines standard form for a parabola with vertex (h, k) and horizontal axis of symmetry as x - h = a(y - k)<SUP>2</SUP> THEN your answer is correct.
nigel said: Put y^2 - 4x - 6y + 9 = 0 into standard form. Is the answer as follows? x = (1/4)(y - 3)^2 please just tell me if the answer is correct, or if not what is the correct answer Thank You Click to expand... IF your book defines standard form for a parabola with vertex (h, k) and horizontal axis of symmetry as x - h = a(y - k)<SUP>2</SUP> THEN your answer is correct.
