Standardization of the conic whose equation is known?

gunza

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Conic equation: [MATH]{4x^{2}−4xy+7y^{2}+12x+6y−9=0}[/MATH]
How is this conic standardized?
 
Conic equation: [MATH]{4x^{2}−4xy+7y^{2}+12x+6y−9=0}[/MATH]
How is this conic standardized?
Please show us what you have tried and exactly where you are stuck.

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Please share your work/thoughts about this problem.
 
This conic equation : [MATH]{4x^{2}-4xy+7y^{2}+12x+6y-9=0}[/MATH]
And it is desired to convert this cone to standard form. (standard form, final conic equation)
 
This conic equation : [MATH]{4x^{2}-4xy+7y^{2}+12x+6y-9=0}[/MATH]
And it is desired to convert this cone to standard form. (standard form, final conic equation)
What is the standard form of a conic section?

What does it look like?
 
What is the standard form of a conic section?

What does it look like?


Converting the general conic equation to standard form (standard equation)
general conic equation is:

[MATH]{4x^{2}−4xy+7y^{2}+12x+6y−9=0}[/MATH]
and standart equation is like:
[MATH]{Ax^{2}+Cy^{2}+F=0}[/MATH]
 
Converting the general conic equation to standard form (standard equation)
general conic equation is:

[MATH]{4x^{2}−4xy+7y^{2}+12x+6y−9=0}[/MATH]
and standart equation is like:
[MATH]{Ax^{2}+Cy^{2}+F=0}[/MATH]
Yours can't be put in that form, unless you are talking about a change of variables (e.g. rotation). Can you tell us more about the assignment? What topics are you studying?
 
Yours can't be put in that form, unless you are talking about a change of variables (e.g. rotation). Can you tell us more about the assignment? What topics are you studying?

I tried a way like this:
1) Identify the conic section using the discriminant: [MATH]{B^{2}-4AC}[/MATH]2) Determine θ using the formula : [MATH]{Tan2θ = \frac{B}{A-C}}[/MATH]3) Calculate [MATH]{A^{'}, B^{'}, C^{'}, D^{'}, E^{'}, F^{'}}[/MATH]4) Rewrite the original equation using [MATH]{A^{'}, B^{'}, C^{'}, D^{'}, E^{'}, F^{'}}[/MATH]
Now,
[MATH]{4x^{2}−4xy+7y^{2}+12x+6y−9=0}[/MATH]
According to the equation x^2, xy, y^2, x, y, and the trailing -9. Their coefficients:
A=4, B=-4, C=7, D=12, E=6, F=-9

1.) [MATH]{B^{2}-4AC <0}[/MATH] ((-4)^2-4x4x7 = 16-112 = -96 < 0) "So this is an ellipse"

2.) [MATH]{Tan2θ = \frac{B}{A-C} = \frac{4}{3} ->θ = 27 "degree"}[/MATH]
3.) There are formulas for [MATH]{A^{'}, B^{'}, C^{'}, D^{'}, E^{'}, F^{'}}[/MATH] Taking B = 0 to get rid of the xy expression, and the others are:
[MATH]{A^{'} = Acos^{2}θ+Bcosθsinθ+Csin^{2}θ}[/MATH] Plug in the angle "θ" 27 degrees and A 'is about 2,96.
[MATH]{B^{'} = 0 }[/MATH][MATH]{C^{'} = Asin^{2}θ+Bsinθcosθ+Ccos^{2}θ}[/MATH] Plug in the angle "θ" 27 degrees and A 'is about 4,73
[MATH]{D^{'} = Dcosθ+Esinθ}[/MATH] Plug in the angle "θ" 27 degrees and A 'is about 13,38
[MATH]{E^{'} = -Dsinθ+Ecosθ}[/MATH] Plug in the angle "θ" 27 degrees and A 'is about -0,06
[MATH]{F^{'} = F = -9}[/MATH]
Since this is an ellipse according to 1, the standard form of the general equation given is:
[MATH]{\frac{(x-h)^{2}}{b^{2}}+\frac{(y-k)^{2}}{a^{2}}=1}[/MATH]it must be.

I've got this:
[MATH]{2,96x^{2}+4,73y^{2}+13,38x-0,06y=9}[/MATH]
Where could I go wrong? In the formulas A 'B' C 'D' E 'F'?
 
I tried a way like this:
1) Identify the conic section using the discriminant: [MATH]{B^{2}-4AC}[/MATH]2) Determine θ using the formula : [MATH]{Tan2θ = \frac{B}{A-C}}[/MATH]3) Calculate [MATH]{A^{'}, B^{'}, C^{'}, D^{'}, E^{'}, F^{'}}[/MATH]4) Rewrite the original equation using [MATH]{A^{'}, B^{'}, C^{'}, D^{'}, E^{'}, F^{'}}[/MATH]
Now,
[MATH]{4x^{2}−4xy+7y^{2}+12x+6y−9=0}[/MATH]
According to the equation x^2, xy, y^2, x, y, and the trailing -9. Their coefficients:
A=4, B=-4, C=7, D=12, E=6, F=-9

1.) [MATH]{B^{2}-4AC <0}[/MATH] ((-4)^2-4x4x7 = 16-112 = -96 < 0) "So this is an ellipse"

2.) [MATH]{Tan2θ = \frac{B}{A-C} = \frac{4}{3} ->θ = 27 "degree"}[/MATH]
3.) There are formulas for [MATH]{A^{'}, B^{'}, C^{'}, D^{'}, E^{'}, F^{'}}[/MATH] Taking B = 0 to get rid of the xy expression, and the others are:
[MATH]{A^{'} = Acos^{2}θ+Bcosθsinθ+Csin^{2}θ}[/MATH] Plug in the angle "θ" 27 degrees and A 'is about 2,96.
[MATH]{B^{'} = 0 }[/MATH][MATH]{C^{'} = Asin^{2}θ+Bsinθcosθ+Ccos^{2}θ}[/MATH] Plug in the angle "θ" 27 degrees and A 'is about 4,73
[MATH]{D^{'} = Dcosθ+Esinθ}[/MATH] Plug in the angle "θ" 27 degrees and A 'is about 13,38
[MATH]{E^{'} = -Dsinθ+Ecosθ}[/MATH] Plug in the angle "θ" 27 degrees and A 'is about -0,06
[MATH]{F^{'} = F = -9}[/MATH]
Since this is an ellipse according to 1, the standard form of the general equation given is:
[MATH]{\frac{(x-h)^{2}}{b^{2}}+\frac{(y-k)^{2}}{a^{2}}=1}[/MATH]it must be.

I've got this:
[MATH]{2,96x^{2}+4,73y^{2}+13,38x-0,06y=9}[/MATH]
You say:

Where could I go wrong? In the formulas A 'B' C 'D' E 'F'?​

Why do you think you had gone wrong?!!
 
You say:

Where could I go wrong? In the formulas A 'B' C 'D' E 'F'?​

Why do you think you had gone wrong?!!

In an example question;
[MATH]{x^{2}+2xy+y^{2}-4\sqrt2y+4=0}[/MATH]
So,
A=1, B=2, C=1, D=0, E=-4(sqrt2) F=4
and tan2Ɵ = pi / 2 Ɵ = pi / 4
[MATH]{x = cosθx^{'}-sinθy^{'}}[/MATH][MATH]{y = sinθx^{'}+cosθy^{'}}[/MATH]
Using θ in these equations, after finding x and y, it is replaced in the original equation.
What is the difference between the formulas I use and these x, y rotation equations?
 
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