habeebe
New member
- Joined
- Nov 2, 2011
- Messages
- 2
Use Newton's method to find all the roots of the equation correct to six decimal places. x1=1+x3
In the problem I had prior to this, my resulting function was factorable into the form a∗b=0, so I knew I had two roots, and could easily find starting values with the intermediate value theorem. With this problem, I worked my way up to f(x)=0=x4+x−1=x(x3+1)−1. It looks like there are two roots, but the −1 is throwing me off. I am not sure how to get my two functions for the two seperate roots, and because of that I can't find my x1's for either root.
How do I get to the next step?
In the problem I had prior to this, my resulting function was factorable into the form a∗b=0, so I knew I had two roots, and could easily find starting values with the intermediate value theorem. With this problem, I worked my way up to f(x)=0=x4+x−1=x(x3+1)−1. It looks like there are two roots, but the −1 is throwing me off. I am not sure how to get my two functions for the two seperate roots, and because of that I can't find my x1's for either root.
How do I get to the next step?