Statistics

[IlanSherer]

Hello

Can you help me please about the next exercise:

The average daily wage of an employee in factory A is 300 dollars, and the standard deviation of wage in the same factory is 50 dollars.
Factory B, which employs three times more than number of employees in factory A (it means - if there are 100 employees in factory A, so in factory B there are 300 employees), pays their employees a standard salary of 200 dollars per day.
Therefore, the standard deviation of the wage of all employees in the two factories is:
a. 50 dollars.
b. 25 dollars.
c. 625 dollars.
d. 2500 dollars.


My incomplete solution:

Therefore, in factory B there are 3*b employees.
And if I understood correctly, the average in factory B is 200 dollars.
I still can't reach a solution, I don't know... maybe I'm in the wrong direction? or I did something wrong?

Thanks a lot!
*Sorry if my english is bad, I will explain again and again if you didn't understand*

 

[IlanSherer]

I think i found it.



50+0=50
Therefore, the answer is a.
Right?

 

[j-astron]

Hi IlanSherer

The question is somewhat ambiguous. But my interpretation of it is that Factory B pays all of its employees exactly $200 per day. I.e. there is no deviation. So the standard deviation of the wages of all the employees in Factory B is 0. If this interpretation is correct, then perhaps that gives you a direction to go in to solve this problem?