straight line joining feet of perpendiculars from (1,1) to 3x-3y-4=0 and 3x+y-6=0

[Kitimbo]

Find the equation of the straight line joining the feet of the perpendiculars drawn from the point (1,1) to the lines 3x-3y-4=0 and 3x+y-6=0.

I couldn't even interprete it

 

[Harry_the_cat]

Find the equation of the straight line joining the feet of the perpendiculars drawn from the point (1,1) to the lines 3x-3y-4=0 and 3x+y-6=0.

I couldn't even interprete it

Step 1: Find the equation of the line perpendicular to the line 3x-3y-4=0 and which passes through the point (1, 1).

Step 2: Find where the perpendicular line (found in step 1) intersects the line 3x-3y-4=0. Call this point A.

Step 3/4: Repeat Steps1/2 for the line 3x+y-6=0. Call this intersection point B.

Step 5: Find the equation of the straight line joining the points A and B.

(Note: The foot of a perpendicular from a point to a line is the point where the perpendicular line and the original line intersect.)

 

[Kitimbo]

Thanks I got it