raymondtamesis said:

I am unsure how to proceed to answer this problem?

A rectangular swimming pool is three times longer than it is wide. The pool is surrounded by a brick walk way 2.5 meters wide on all four sides. Find the dimensions of the pool if the area of the brick walk way is 265 meters square :?:

I think galactus has confused perimeter with area in his solution. So, I'll offer a response based on area (as the problem states).

let x = width of pool

then 3x = length of pool

Area = length * width

Area of pool = 3x*x

Area of pool = 3x<SUP>2</SUP>

The walkway adds 2.5 + 2.5 or 5 m to both the length and the width of the pool. For the rectangle formed by the pool and walkway together, then,

x + 5 = width

3x + 5 = length

Area of pool and walkway together = (3x + 5)(x + 5)

You'll need to multiply these binomials together.....

Would you agree with this?

Area of pool and walkway together - Area of pool = area of walkway

Substitute the expressions we have for the areas:

(3x + 5)(x + 5) - 3x<SUP>2</SUP> = 265

There's your equation....you can solve it for x, and then determine the dimensions of the pool.

I hope this helps you.