Hint:Question- find the integral of (y^2-1)dx-2dy=0
My approach has been to separate x term on one side and y term on another side..
But then I do not know how to integrate 2dy/(y^2-1).
Please help, and do mention the final answer.
Hint:
2/(y^2 - 1) = 1/(y - 1) - 1/(y + 1)
Continue ....
You should differentiate your answer to confirm/discard the result.IS THIS THE CORRECT SOLUTION?
Bravo?IS THIS THE CORRECT SOLUTION?