Hello friends. I think I have most of this problem worked out. original f(x) is x(3x - 9)^3 so u = 3x - 9 and u' = 3
f '(x)= x(3)(3x-9)^2(3) + (3x-9)(1) then f '(x)= 9x(3x-9)^2 + (3x-9)^3 I am positive what I have so far is correct. But I don't know what to do with the (3x-9)^3 any help is appreciated.
f '(x)= x(3)(3x-9)^2(3) + (3x-9)(1) then f '(x)= 9x(3x-9)^2 + (3x-9)^3 I am positive what I have so far is correct. But I don't know what to do with the (3x-9)^3 any help is appreciated.