Stuck on number problems

tytyman

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Oct 4, 2011
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1).The total of two numbers is 35. Four times the larger number is 4 less than five times the smaller number. Find the two numbers.

2). The sum of two numbers is 57.The larger of the two numbers is 9 less than twice the smaller, find the two numbers.

Needs some help, Thanks
 
Hello, tytyman!

It is a matter of translating the words to algebra ... carefully.


1)The total of two numbers is 35.
Four times the larger number is 4 less than five times the smaller number.
Find the two numbers.

Let n\displaystyle n = larger number.

Then 35n\displaystyle 35-n = smaller number.


Four4  times×  largern  is=  four less4  than+  five5  times×  smaller(35n)\displaystyle \underbrace{\text{Four}}_4\; \underbrace{\text{times}}_{\times}\;\underbrace{\text{larger}}_{n}\;\underbrace{\text{is}}_{=}\; \underbrace{\text{four less}}_{-4}\;\underbrace{\text{than}}_{+}\;\underbrace{\text{five}}_{5}\;\underbrace{\text{times}}_{\times}\;\underbrace{\text{smaller}}_{(35-n)}

The equation is: .4n  =  4+5(35n)\displaystyle 4n \;=\;-4 + 5(35-n)




2) The sum of two numbers is 57.
The larger of the two numbers is 9 less than twice the smaller.
Find the two numbers.

Let n\displaystyle n = larger number.

Then 57n\displaystyle 57-n = smaller number.


Largern  is=  9 less9  than+  twice2×  smaller(57n)\displaystyle \underbrace{\text{Larger}}_{n} \; \underbrace{\text{is}}_{=} \; \underbrace{\text{9 less}}_{-9} \;\underbrace{\text{than}}_{+} \;\underbrace{\text{twice}}_{2\:\times}\;\underbrace{\text{smaller}}_{(57-n)}

The equation is: .n  =  9+2(57n)\displaystyle n \;=\;-9 + 2(57-n)
 
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