nicholaskong100
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- Aug 1, 2021
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Well, using standard standard notation means the [imath]S=\{1,2,3\}[/imath] is the whole space.Well, you add the fractions which gives you 3/3. 1 can also be written as 3/3. Subtract 3/3 with 3/3 and you get zero for the second sample point. P{1} = \frac{1}{3} and P{3} = \frac{2}{3}.
From what I am understanding if the problems have some givens, does that mean I can add all the givens = 1 as the sample space as how you wrote it?
Here is how I would start:
Wow, that certainly makes thing much easier to look at. x = 1/3, y = 0 and z = 2/3.Here is how I would start:
If P({1}) = x, P({2}) = y, and P({3}) = z, we have
P({1,2}) = 1/3 so x + y = 1/3P({2,3}) = 2/3, so y + z = 2/3P({1,2,3}) = 1, so x + y + z = 1
Solve that system.
x = 1/3, y = 0 and z = 2/3.Well, using standard standard notation means the [imath]S=\{1,2,3\}[/imath] is the whole space.
So that [imath]\mathcal{P}(S)=1[/imath] What did you find for [imath]\mathcal{P}(\{1\})~\&~\mathcal{P}(\{3\})~?[/imath]