Hi all,
I've been trying to solve this question that involves logarithms and I just can't get anywhere with it!
Here is the problem:
9x - 5・2x-3/2 = 2x+1/2 + 2・32x+1
I've familiarized myself with some logarithm rules and this is as far as I got...
=> 32x - 5・2x-3/2 = 2x+1/2 + 2・32x-1
=> log(32x) - log(5・2x-3/2) = log(2x+1/2) + log(2・32x-1)
(Am I even allowed to "log" every term, like how I did in the second line?)
=> 2xlog(3) - [log(5)+log(2x-3/2)] = (x+1/2)log(2) + log(2) + (2x-1)log
=> 2xlog(3) - log(5) - (x-3/2)log(2) = (x+1/2)log(2) + log(2) + (2x-1)log...
At this point, I am not really sure if I am going in the right direction.
Could someone please suggest some tips or advice on how I should tackle this problem? Any help is very much appreciated
I've been trying to solve this question that involves logarithms and I just can't get anywhere with it!
Here is the problem:
9x - 5・2x-3/2 = 2x+1/2 + 2・32x+1
I've familiarized myself with some logarithm rules and this is as far as I got...
=> 32x - 5・2x-3/2 = 2x+1/2 + 2・32x-1
=> log(32x) - log(5・2x-3/2) = log(2x+1/2) + log(2・32x-1)
(Am I even allowed to "log" every term, like how I did in the second line?)
=> 2xlog(3) - [log(5)+log(2x-3/2)] = (x+1/2)log(2) + log(2) + (2x-1)log
=> 2xlog(3) - log(5) - (x-3/2)log(2) = (x+1/2)log(2) + log(2) + (2x-1)log...
At this point, I am not really sure if I am going in the right direction.
Could someone please suggest some tips or advice on how I should tackle this problem? Any help is very much appreciated