sum and difference of cubes formulas

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juliag

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Nov 5, 2010
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Hi there ok I'm stuck! It's sum and difference of cube formulas involving a varible that is to the 6th:

64s to the 6th + t to the 6th

I am having trouble getting started. I understand the procedure for the formula just not when it is not to the 3rd exponent. Please HELP! Thanks alot :)
 
\(\displaystyle 64s^{6}+t^{6}\)

\(\displaystyle (4s^{2})^{3}+(t^{2})^{3}\)

Now, you have the sum of two cubes.

Can you finish?.
 
juliag said:
Hi there ok I'm stuck! It's sum and difference of cube formulas involving a varible that is to the 6th:

64s to the 6th + t to the 6th

I am having trouble getting started. I understand the procedure for the formula just not when it is not to the 3rd exponent. Please HELP! Thanks alot :)
Click to expand...

Is your problem to factorize:

\(\displaystyle 64^6 \ + \ t^6\)

If yes then start with:

\(\displaystyle (64^2)^3 \ + \ (t^2)^3\)

Now continue.....
 
I am not even at that level of math. i am in remedio..so I am prepared for even more challenging math...Oh boy!! what grade level of math are you in..? I just wanted to see other student's to see what math level they're on. I am hanging on to remedio math in college...I believe I can do it too!! so can you!!! :D
 
I am also in college I am upgrading my courses for medical school. What are you in college for?
 
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