Good Day All
Hope you are keeping well.
I understand the basic concept of sum/difference of cubes where a^3+b^3 = (a+b)(a^2-ab+b^2) and a^3-b^3 = (a-b)(a^2+ab+b^2)
But I've been thrown a curveball of factorizing
(x-y)^3 - (x+y)^3
now I've been given the solution of
-2y(3x^2+y^2)
without the in-between steps. I don't understand how to get to this answer. Any assistance would be appreciated.
Thank you
Dalmain
Hope you are keeping well.
I understand the basic concept of sum/difference of cubes where a^3+b^3 = (a+b)(a^2-ab+b^2) and a^3-b^3 = (a-b)(a^2+ab+b^2)
But I've been thrown a curveball of factorizing
(x-y)^3 - (x+y)^3
now I've been given the solution of
-2y(3x^2+y^2)
without the in-between steps. I don't understand how to get to this answer. Any assistance would be appreciated.
Thank you
Dalmain