sum of 3 consec. integers is 33 more than least integer

[josh brown]

The sum of three consecutive integers is 33 more than the least of the integers. Find the integers.

 

[stapel]

i) Pick a variable for the smallest of the three numbers.

ii) In terms of the variable in (i), create an expression for the next integer.

iii) In terms of the variable in (i), create an expression for the third integer.

iv) Sum the variable from (i) and the expressions from (ii) and (iii). Simplify.

v) Create an expression, in terms of (i), for a value 33 more than the smallest number.

vi) Set (iv) equal to (v), and solve.

vii) Back-solve for the values of the other two numbers.

If you get stuck, please reply showing how far you have gotten in following the instructions. Thank you!

Eliz.

 

[josh brown]

Does this represent the work need to show and obtain answer??
(x) + (x+1) + (x+2) = x + 33
3x + 3 = 1x + 33
-1x -3 -1x

2x /2 = 30/2

x = 15

The integer is 15, 16, and 17. Is this correct? Thanks

 

[skeeter]

check the result yourself ... do the three integers 15, 16, and 17 work in the original problem statement?

The sum of three consecutive integers is 33 more than the least of the integers.