T trip20 New member Joined Nov 4, 2006 Messages 22 Dec 15, 2006 #1 Last question, promise! Not sure how to write out a summation but here it goes: 6 E (1/3)^i+1 i=1 I know this means: (1/3)^(6+1)+(1/3)^(5+1)+(1/3)^(4+1) .....(1/3)^(1+1) but I'm not sure how to write this out and solve?
Last question, promise! Not sure how to write out a summation but here it goes: 6 E (1/3)^i+1 i=1 I know this means: (1/3)^(6+1)+(1/3)^(5+1)+(1/3)^(4+1) .....(1/3)^(1+1) but I'm not sure how to write this out and solve?
U Unco Senior Member Joined Jul 21, 2005 Messages 1,134 Dec 15, 2006 #2 Again with the parentheses... anyway, look up the sum of a geometric series.
