Good Evening,
I am struggling with a survival function problem, I always get a value over 1, just wondering if someone could have a look at my maths and give me a hand.
so given the function
f= qpt^(p-1)/(((q+t^(p))^2) where q>0 and p>0
I get
F(t) as = -q/(q+(t^p))
S(t) = 1-F(t) as 1 - (-q/(q+(t^p)))
if I hypothetically say q is 2 and p is 2 and t is 1
then trying to plug numbers in survival function we get 1 - (-2/(2+(1^2))) = 1 - (-2/3) = 1.6666666 which cannot be a survival function as it is above 1...........
I'm lost........
I am struggling with a survival function problem, I always get a value over 1, just wondering if someone could have a look at my maths and give me a hand.
so given the function
f= qpt^(p-1)/(((q+t^(p))^2) where q>0 and p>0
I get
F(t) as = -q/(q+(t^p))
S(t) = 1-F(t) as 1 - (-q/(q+(t^p)))
if I hypothetically say q is 2 and p is 2 and t is 1
then trying to plug numbers in survival function we get 1 - (-2/(2+(1^2))) = 1 - (-2/3) = 1.6666666 which cannot be a survival function as it is above 1...........
I'm lost........